Volume= (Pi x R^3)/3 x [2 - 3xCos(angle) + Cos (angle)^3]
John
--Previous Message--
: Been there, done that, the volume is
: 8.66mls. This will raise the CR from
: 9.5 to roughly 11.5.
:
: Although the formula I used was:
:
: Volume= (ð x R3)/3 x [2 - 3xCos(angle)
: + Cos (angle) 3]
: where 'angle' was the angle subtended
: by the sector of the sphere (that the
: dome represents) at the centre of the
: sphere. THAT was the difficult bit.
: This procedure allows you to do the
: calcs from just the height and width of
: the dome.
: See Appendix to :
: http://www.totallytriumph.net/spitfire/skimming_your_head.shtml
:
: If you want to measure the dome, place
: the piston in a bore, at a fixed height
: (best on a conrod, on the crank). Seal
: the bore with vaseline on the piston
: rings.
:
: Theoretical volume of bore= ðR^2H
: Measure the bore volume with a burette,
: as for chamber measurement. The
: difference from the theoretical volume
: is the volume of the dome.
: John
:
: --Previous Message--
: In this day of online resources I still
: keep a copy of the CRC Math Tables book
: at work. It can be handy for
: calculations like this.
:
: If the dome is really a true section of
: a sphere, you can calculate its volume
: using the formula:
: V = 1/6 x Pi x H x ((3 x R x R) + (H x
: H))
: Where H is the height of the dome,
: and R is the Radius of the dome on top
: of the Piston.
:
: I am not sure how I would try to
: measure this by CC(ing) the piston top
: so calculations sound good to me. The
: other option is to hunt the piston
: specs to confirm the 10cc that Steve
: mentioned.
:
: Doug L.
:
:
: --Previous Message--
: I believe the popup domes on the
: Hepolites will be about 10cc's.
:
:
:
:
:
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