Re: Tesla patent 512340
Posted by Jerry Anderson on 3/27/2006, 3:10 pm, in reply to "Re: Tesla patent 512340"
: : Again thank you Bert.
: You mentioned that a mulitlayer coil would be better suited and easier to
: wind than flat pancaked ones. I'm not quite following what the difference
: would be. The coil that I had planned to use was of course 300 turns of
: 23awg with a 2" aircore and then pancake 10-15 other layers on top
: with each connected in series.
: Tesla's patent referred to a single layer spiral with NO stacking of
: layers (since this would actually defeat the purpose of the patent). If
: you wound a series of single layers and connected them in series, this
: would create a multilayer coil.
: How is the mulitlayer coil you're talking
: about built? Lastly as I'm using about a maximum of 300vdc into the coils
: would it be better to use more turns of a narrower gauge wire or stick
: with the gauge I have?
: I'd recommend simply winding flat layers, one on top of the other, using
: tape to separate layers if necessary. Using an applied voltage of 300 VDC,
: you may also need to have some form of external current limiting (beyond
: using just wire resistance). You'll also need to look at the amount of
: physical space you have available for the windings. Because of the
: relatively low wire resistance of #23 AWG wire, you may need a way to
: externally limit the current that will flow through the coil, or limit the
: ON time versus OFF time (duty cycle) so that the winding doesn't overheat.
: Looking at 23 AWG: Close-winding 23 AWG magnet wire will only give you
: about 41 turns/inch, so no matter how you wind it, a 4500 turn coil will
: occupy considerable space and weight (probably at least 7-8 pounds of
: magnet wire). 23 AWG has ~20.3 ohms/1000 feet, and about 648 feet/pound,
: so you'll need to bend the numbers for your proposed coils. I'd suggest
: using a significantly smaller wire diameter (perhaps #28 or so) so that
: you can get higher winding density, particularly if used with a high duty
: cycle. Assuming 8 pounds of wire (almost one 1 mile of wire), the
: resistance would be about 105 ohms. For 300 volts, the steady state
: current would be 2.85 amps, and the power dissipated in the coil (as heat)
: would be about 855 watts. With no external current limiting, the coil will
: get VERY hot, VERY quickly, and will burn up.
:Sorry I took so long getting back to you, work is occupying way too much of my time. =)
I see your point on the smaller wire diameter makes perfect sense. My original intention was to use the heavier gauge to get a stronger field. But from what I'm understanding is that I can achieve the same magnetic field by using more windings of a smaller gauge. Is that correct?
If you have time can you take a peek at the guy who posted his notes and schematics on his water powered 1978 V8 Camaro. It's at http://www.waterpoweredcar.com/1978camero.html and let me know what you think of his circuit. His piggy backing of a half wave rectified signal on top of the distributor output through relay contacts appears to be drawn incorrectly.
I will have shortly two motors on test stands, one Honda 4 cylinder and 1 12A rotary motor for testing of several ideas we've read about. This one intrigues us the most. We would greatly appreciate your opinion on this.
Thanks very much for your time.